16=0.50x^2

Solution for 16=0.50x^2 equation:

16=0.50x^2

We move all terms to the left:

16-(0.50x^2)=0

We get rid of parentheses

-0.50x^2+16=0

We add all the numbers together, and all the variables

-0.5x^2+16=0

a = -0.5; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-0.5)·16
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{2}}{2*-0.5}=\frac{0-4\sqrt{2}}{-1}
=-\frac{4\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{2}}{2*-0.5}=\frac{0+4\sqrt{2}}{-1}
=\frac{4\sqrt{2}}{-1}
$